Precise Duration

Usage

Auto-format usually chooses most suitable two units.

See abbreviation options

final epoch = Moment.fromMillisecondsSinceEpoch(0);
final now = DateTime(2023, DateTime.july, 14).toMoment();

print(epoch.fromPrecise(now)); // 53 years 7 months ago

A little crazy example

final nextYear = now.add(const Duration(days: 365));

print(nextYear.fromPrecise(
  now,
  format: DurationFormat.all,
  omitZeros: false, // default true
  form: UnitStringForm.mid,
  delimiter: ", ", // default " "
));
// in 1 yr, 0 mo, 0 day, 0 hr, 0 min, 0 sec

Discarding smaller units

When a duration is formatted, any units that are smaller than the smallest unit given in DurationFormat are discarded. Demonstration:

const duration1d1h = Duration(days: 1, hours: 1);

duration1d1h.toDurationString(format: DurationFormat([DurationUnit.day]), dropPrefixOrSuffix: true); // a day (here we lose precision of 1 hour)
duration1d1h.toDurationString(format: DurationFormat([DurationUnit.hour]), dropPrefixOrSuffix: true); // 25 hours

Using on Duration

Duration(days: 67, hours: 3, minutes: 2).toDurationString(
  MomentLocalizations.de(),
  form: UnitStringForm.mid,
); // in 2 Mo. 7 Tg.

Formatting

By default, the most suitable format is chosen from default formats.

You can create a DurationFormat with DurationUnit list, in order. This is useful if you need to display specific units. For example, "x days left" countdown.

final DurationFormat d = DurationFormat([DurationUnit.day]);

const Duration(days: 13).toDurationString(format: d); // in 13 days

Default formats

Format	units
DurationFormat.ym	year, month
DurationFormat.md	month, day
DurationFormat.dh	day, hour
DurationFormat.hm	hour, minute
DurationFormat.ms	minute, second
DurationFormat.s	second
DurationFormat.wd	week , day (only if includeWeeks: true)